SOLUTION: solve each system by the substitution method. 1) 2x^2-y^2=6 2) y=x^2-3

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Question 750196: solve each system by the substitution method.
1) 2x^2-y^2=6
2) y=x^2-3
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2=y%2B3


%0D%0A2%28y%2B3%29-y%5E2=6%0D%0A



y%5E2-2y=0



so y=0 or y=2



y=0:

%0D%0Ax%5E2=y%2B3=3%0D%0A


%0D%0Ax=sqrt%283%29%0D%0A

or



%0D%0Ax=-sqrt%283%29%0D%0A


y=2:

%0D%0Ax=sqrt%285%29%0D%0A
or
%0D%0Ax=-sqrt%285%29%0D%0A

solutions

(-sqrt(3),0)
(sqrt(3),0)
(-sqrt(5),2)
(sqrt(5),2)



:)