SOLUTION: Miami and Pittsburg are 1000 miles apart. A plane flew into a 50mph headwind from miami to pittsburg. on the return flight the 50mph wind became a tailwind. The lane was in the air
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Question 750065: Miami and Pittsburg are 1000 miles apart. A plane flew into a 50mph headwind from miami to pittsburg. on the return flight the 50mph wind became a tailwind. The lane was in the air a total of 4.5 hrs. for the roundtrip. what would have been the planes average speed without the wind? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Miami and Pittsburg are 1000 miles apart. A plane flew into a 50mph headwind from miami to pittsburg. on the return flight the 50mph wind became a tailwind. The lane was in the air a total of 4.5 hrs. for the roundtrip. what would have been the planes average speed without the wind?
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p = plane's airspeed
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1000/(p - 50) + 1000/(p + 50) = 4.5
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1000*(2p) = 4.5*(p^2 - 2500)
4000p = 9p^2 - 22500
9p^2 - 4000p - 22500 = 0
