SOLUTION: find the center of of the circle defined by the equation x^2+y^2+16x-16y+79=0

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Question 749826: find the center of of the circle defined by the equation x^2+y^2+16x-16y+79=0
Answer by kibauu(44) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2By%5E2%2B16x-16y%2B79=0
the circle has common equation x%5E2%2By%5E2%2BAx%2BBx%2BC=0
the center of this eq. -A%2F2,-%28B%2F2%29
so you have (-8,8)