SOLUTION: Find the standard form for the equation of the line which passes through the point (-1,-2) and is parallel to the line whose equation is 6x+2y=4?

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Question 74978: Find the standard form for the equation of the line which passes through the point (-1,-2) and is parallel to the line whose equation is 6x+2y=4?
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Find the standard form for the equation of the line which passes through the point (-1,-2) and is parallel to the line whose equation is 6x+2y=4?
Parallel lines have equal slopes, so our line has the same slope as 6x+2y=4.
To find the slope of the equation of a line, put the line in slope-intercept form: highlight%28y=mx%2Bb%29, where m=slope and (0,b)=y-intercept
6x%2B2y=4
6x-6x%2B2y=-6x%2B4
2y=-6x%2B4
2y%2F2=-6x%2F2%2B4%2F2
y=-3x%2B2 The slope is, m=-3
Therefore, our line has a slope of m=-3 and goes through the point (-1,-2).
Some teachers use the slope intercept form of a line to find b and make the equation.
Others use the point-slope formula (my preference): highlight%28y-y%5B1%5D=m%28x-x%5B1%5D%29%29, where m=slope and (x1,y1)=given point.
(x1,y1)=(-1,-2) and m=-3
y-%28-2%29=-3%28x-%28-1%29%29
y%2B2=-3%28x%2B1%29
y%2B2=-3x-3
The standard form of a line is highlight%28Ax%2BB=C%29, where A,B, and C are integers and most books and teachers prefer that A be positive.
3x%2By%2B2=3x-3x-3
3x%2By%2B2=-3
3x%2By%2B2-2=-3-2
highlight%283x%2By=-5%29
Happy Calculating!!!!