SOLUTION: Here is another problem I need help with. Can somebody help me thank you!!!!! An airplane flies between two cities 650 kilometers apart, traveling with a wind of 35 miles p

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Question 74970: Here is another problem I need help with. Can somebody help me thank you!!!!!
An airplane flies between two cities 650 kilometers apart, traveling
with a wind of 35 miles per hour going, and against the same wind
when returning. The trip out takes one less hour than the return trip. What
is the speed of the plane in still air?

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
time = distance/rate
s = speed of plane in still air

This leads to 650%2F%28s%2B35%29%2B1=650%2F%28s-35%29 or %28650%2Bs%2B35%29%2F%28s%2B35%29=650%2F%28s-35%29

cross multiplying gives 650s%2Bs%5E2%2B35s-%28650%2A35%29-35s-35%5E2=650s%2B%28650%2A35%29

Combining and rearranging terms gives s%5E2=1335%2A35 or s=216.16 mph