SOLUTION: you have been asked to design a small box. the width is 1 inch more than the depth. length is 3 inches more than the depth. volume is 30 cubic inches. what are the dimensions?

Algebra ->  Volume -> SOLUTION: you have been asked to design a small box. the width is 1 inch more than the depth. length is 3 inches more than the depth. volume is 30 cubic inches. what are the dimensions?      Log On


   



Question 749671: you have been asked to design a small box. the width is 1 inch more than the depth. length is 3 inches more than the depth. volume is 30 cubic inches. what are the dimensions?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
you have been asked to design a small box.
the width is 1 inch more than the depth.
Let depth be "x"
Then width is "x+1"
---
length is 3 inches more than the depth.
And length is "x+3"
----
volume is 30 cubic inches.
x(x+1)(x+3) = 30 in^3
------
x(x^2+4x+3) = 30
x^3 + 4x^2+3x-30 = 30
Solution: x = 2
------------------------
what are the dimensions?
depth = 2 in
width = 3 in
length = 5 in
==================
Cheers,
Stan H.
===================