SOLUTION: how many real number solutions? 4x^2+8x-4=0

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Question 749636: how many real number solutions? 4x^2+8x-4=0
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
two:
sqrt%28+8%5E2-4%2A4%2A%28-4%29+%29=8sqrt%282%29
so there are 2 irrational solutions

:)