SOLUTION: the question is to solve for x .. log base 3 (2x+5) - Log base 3 (x-8) =1 ive gotten as far as log(2x+5/x-8) = 1 and now im stuck

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: the question is to solve for x .. log base 3 (2x+5) - Log base 3 (x-8) =1 ive gotten as far as log(2x+5/x-8) = 1 and now im stuck       Log On


   

Question 749522: the question is to solve for x ..
log base 3 (2x+5) - Log base 3 (x-8) =1
ive gotten as far as log(2x+5/x-8) = 1 and now im stuck
Found 2 solutions by Alan3354, timvanswearingen:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
the question is to solve for x ..
log base 3 (2x+5) - Log base 3 (x-8) =1
ive gotten as far as log(2x+5/x-8) = 1 and now im stuck
====================
1+=+log%283%2C3%29
----
log%283%2C%282x%2B5%29%2F%28x-8%29%29+=+log%283%2C3%29
%282x%2B5%29%2F%28x-8%29+=+3

Answer by timvanswearingen(106) About Me  (Show Source):
You can put this solution on YOUR website!
From where you are, raise 3 to both sides (because it's base 3) to get rid of the log:
log%28%282x%2B5%29%2F%28x-8%29%29+=+1


3%5E%28log%28%282x%2B5%29%2F%28x-8%29%29%29+=+3%5E1 The top is getting cut off, sorry.

%282x%2B5%29%2F%28x-8%29=3
Now use cross products to solve:
%282x%2B5%29%2F%28x-8%29=3%2F1
1%282x%2B5%29=3%28x-8%29
Distribute:
2x%2B5=3x-24
Subtract 2x from both sides:
5=x-24
Add 24 to both sides:
29=x