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Question 749471: please help me with this problem
1.y=-3x-6;(-1,5) Write the equation of a line parallel to the given line but passing through the given point.
2. y=-1/3x-4;(-6,-3)Write the equation of a line perpendicular to the given line but passing through the given point.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 1.y=-3x-6;(-1,5) Write the equation of a line parallel to the given line but passing through the given point.
Slope of the given equation is -3, so the parallel line has slope = -3.
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Form: y = mx + b
Solve for "b":
5 = -3*-1 + b
b = 2
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Equation:
y = -3x + 2
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2. y=-1/3x-4;(-6,-3) Write the equation of a line perpendicular to the given line but passing through the given point.
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The given line has slope -1/3, so the perpendicular line has slope 3.
Form: y = mx + b
-3 = 3*-6 + b
-3 = -18 + b
b = 15
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Equation:
y = 3x + 15
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Cheers,
Stan H.
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