SOLUTION: How to write these equations in logarithmic form? 49=(1/7)^-2 a=b^c

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Question 749444: How to write these equations in logarithmic form?
49=(1/7)^-2
a=b^c
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
How to write these equations in logarithmic form?
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Logs are exponents.
The base is what's raised to the exponent
49=(1/7)^-2
log%281%2F7%2C49%29+=+-2
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a=b^c
log%28b%2Ca%29+=+c