SOLUTION: how do i solve {{{ ln(x-1)-ln(x+1)=1 }}}

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Question 749398: how do i solve +ln%28x-1%29-ln%28x%2B1%29=1+
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
+ln%28x-1%29-ln%28x%2B1%29=1+
+ln%28%28x-1%29%2F%28x%2B1%29%29+=+1+
+ln%28%28x-1%29%2F%28x%2B1%29%29+=+ln%28e%29
%28x-1%29%2F%28x%2B1%29+=+e
x - 1 = ex + e
x - ex = 1 + e
x(1 - e) = 1 + e
x = (1 + e)/(1 - e)
---------
1 - e is negative --> x is negative.
--> ln(x-1) is ln(negative)
--> no solution.