Question 749305: A father is four times as old as his son and his daughter is five years younger than her brother. If their combined ages amount to 73 years, find the age of each
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! A father is four times as old as his son and his daughter is five years younger than her brother.
If their combined ages amount to 73 years, find the age of each
:
Let f = father's age
let s = son's age
let d = daughter's age
:
Write an equation for each statement:
:
"A father is four times as old as his son"
f = 4s
:
"his daughter is five years younger than her brother."
d = s-5
:
"their combined ages amount to 73 years,"
f + s + d = 73
replace f with 4s, replace d with (s-5)
4s + s + (s-5) = 73
6s = 73 + 5
6s = 78
s = 78/6
s = 13 yrs is son's age
:
I'll let you find f and d, check your solutions in the total age
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