SOLUTION: at 6 a.m. Nancy left Chicago and headed south at 20 miles per hour. At 8 a.m. Karen left the same place headed south on the same road. IF karen was 50 miles ahead by 1 p.m. on the

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: at 6 a.m. Nancy left Chicago and headed south at 20 miles per hour. At 8 a.m. Karen left the same place headed south on the same road. IF karen was 50 miles ahead by 1 p.m. on the       Log On

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Question 749181: at 6 a.m. Nancy left Chicago and headed south at 20 miles per hour. At 8 a.m. Karen left the same place headed south on the same road. IF karen was 50 miles ahead by 1 p.m. on the same day, what was her speed?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
at 6 a.m. Nancy left Chicago and headed south at 20 miles per hour.
rate = 20 mph ; time = x hrs
distance = 20x miles where x is time after 6 a.m.
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At 8 a.m. Karen left the same place headed south on the same road. IF karen was 50 miles ahead by 1 p.m. on the same day, what was her speed?
distance = 20x+50 miles; time = 5 hrs ; rate = d/t = 4x+10 mph
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Since x = time from 6am to 1pm = 7 hrs
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Karen speed = 4x+10 = 4*7+10 = 38 mph
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Cheers,
Stan H.
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