Question 749174: ln x + ln (x+1-e) = 1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! ln x + ln (x+1-e) = 1
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ln[x(x+1-e)] = 1
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x^2+x-ex = e
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x^2 + x(1-e) - e = 0
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x = [e-1 +- sqrt[(1-e)^2 - 4(-e)]/2
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x = [e-1 +- sqrt[e^2-2e+1 + 4e]/2
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x = [e-1 +- sqrt[e^2+2e+1]/2
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x = [e-1 +- e+1]/2
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x = 2e/2 = e or x = -2/2 = -1
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x cannot be negative
Only Solution: x = e
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Cheers,
Stan H.
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