SOLUTION: Please help me with this problem... 1. Solve the given nonlinear system by the addition method. A. 4x^2–2y^2= –2 B. x^2+4y^2=40 Please show me the steps. thank you

Algebra ->  Systems-of-equations -> SOLUTION: Please help me with this problem... 1. Solve the given nonlinear system by the addition method. A. 4x^2–2y^2= –2 B. x^2+4y^2=40 Please show me the steps. thank you      Log On


   



Question 749140: Please help me with this problem...
1. Solve the given nonlinear system by the addition method.
A. 4x^2–2y^2= –2
B. x^2+4y^2=40

Please show me the steps.
thank you

Answer by josgarithmetic(39614) About Me  (Show Source):
You can put this solution on YOUR website!
You want to multiply one equation or both equations by constants to make the coefficients of either x^2 or y^2 match. Then you either subtract one equation from the other or add one equation to the other. This will give you one resulting equation with one unknown variable.

One way for your given equations can be this:
Multiply equation A by +2.
Add equation A to equation B.
Solve for the variable, x, from the resulting equation. Now use either original equation and solve for y.