Question 749079: A survey is being planned to estimate, with a 98% confidence interval, the mean amount of time per week that seniors spend watching television. The population standard deviation is known to be 5.2 hours. What sample size will be required to obtain an estimate that is within 0.5 hours of the population mean?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A survey is being planned to estimate, with a 98% confidence interval, the mean amount of time per week that seniors spend watching television. The population standard deviation is known to be 5.2 hours. What sample size will be required to obtain an estimate that is within 0.5 hours of the population mean?
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Since E = z,
n = [z*s/E]^2
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n = [2.3263*5.2/(1/2)]^2
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n = 586 when rounded up
Cheers,
Stan H.
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