SOLUTION: Can someone help me with this one?
I hope I write this out right...
(-3*10^-3) (2*10^2)=
I think I have some of it. I get to -6*1-^-5= (and then I am lost - if that is even
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-> SOLUTION: Can someone help me with this one?
I hope I write this out right...
(-3*10^-3) (2*10^2)=
I think I have some of it. I get to -6*1-^-5= (and then I am lost - if that is even
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Question 748714: Can someone help me with this one?
I hope I write this out right...
(-3*10^-3) (2*10^2)=
I think I have some of it. I get to -6*1-^-5= (and then I am lost - if that is even right) Can someone show me how to do this. My text book is useless in explanations. Thanks! Found 2 solutions by stanbon, rothauserc:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! (-3*10^-3) (2*10^2)
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= -3*2*10^-3*10^2
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= -6*10^-1
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= -6/10
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= -0.6
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Cheers,
Stan H.
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You can put this solution on YOUR website! we are asked to evaluate
(-3*10^-3) (2*10^2)= (-3/10^3) * (2*10^2) note that 10^-3 = 1/10^3
= (-3/10) * (2) cancel 10^2 from numerator and denominator
= -6/10
= -3/5
(