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Question 748574: what is the equation of the line perpendicular to 3x+2y=5 and having y- intercept of (0,1)
could you please show all the steps for solving this problem? I am 50 yrs old and new to algebra.
Thanks
Tonya
Found 2 solutions by timvanswearingen, unlockmath:
Answer by timvanswearingen(106)   (Show Source):
You can put this solution on YOUR website! First, find the slope of 3x+2y=5.
To do this, get it into slope-intercept form (y=mx+b where m is the slope and +b is the intercept.)
Subtract 3x from both sides:
Divide both sides by 2:
The coefficient of x is the slope in this equation, so the slope is:
To find a perpendicular slope, you flip it over and change the sign, so it will go from:
To:
So you want the line with slope 2/3 that has a y-intercept of 1 as required by the problem.
With slope-intercept form (y=mx+b), you just need to plug in your slope, m, which is 2/3 and your y-intercept, +b, which is positive 1:
Answer by unlockmath(1688)  (Show Source):
You can put this solution on YOUR website! Hello,
Couple ways to solve this.
Let's put this 3x+2y=5 into a y=mx+b form.
y=-3/2(x)+5/2
For a line to be perpendicular we change the slope (flipping m and change the sign)to:
y=2/3(x)+b
Since we are given the y-intercept of (0,1) we replace b with 1 as:
y=2/3(x)+1
This is very brief and rote explanation.
Hope this helps.
I suggest you get my book at www.math-unlock.com to give a deeper understanding of the basics of math.
RJ
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