SOLUTION: Find 3 consecutive integers such that 5 times the 2nd equals twice the sum of the 1st and 3rd.

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Question 748571: Find 3 consecutive integers such that 5 times the 2nd equals twice the sum of the 1st and 3rd.
Answer by timvanswearingen(106) About Me  (Show Source):
You can put this solution on YOUR website!
Let the smallest integer be x, then the middle is x+1 and the largest is x+2.
5 times the 2nd equals twice the sum of the 1st and 3rd:
5%28x%2B1%29=2%28x%2B%28x%2B2%29%29
5x%2B5=2%282x%2B2%29
5x%2B5=4x%2B4
x%2B5=4
x=+-1
The other numbers are x+1 and x+2, so they are 0 and 1.