Question 748315: $25,000 invested in two accounts, one yielding 8% and the other yielding 10%. A total of $2,380.00 in interest was received at the end of the year. How much was invested in each account?
Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! .10X+.08(25,000-X)=2,380
.10X+2,000-.08X=2,380
.02X=2,380-2,000
.02X=380
X=380/.02
X=$19,000 AMOUNT INVESTED @ 10%
25,000-19000=$6,000 AMOUNT INVESTED @ 8%.
PROOF:
.10*19,000+.08*6,000=2,380
1,900+480=2,380
2,380=2,380
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