SOLUTION: if the base of a right triangle measures 30 feet and the hypotenuse measures 45 feet, what is the hight of the triangle

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Question 748287: if the base of a right triangle measures 30 feet and the hypotenuse measures 45 feet, what is the hight of the triangle
Found 2 solutions by Cromlix, timvanswearingen:
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
This is a Pythagoras question.
The triangle is lettered A,B,C
The base is BC and the hypotenuse is AC
The height is AB
AB^2 + BC^2 = AC^2
AB^2 = AC^2 - BC^2
AB^2 = 45^2 - 30^2
AB^2 = 2025 - 900
AB^2 = 1125
AB = square root of 1125
AB = 33.5 feet. (the height)

Answer by timvanswearingen(106) About Me  (Show Source):
You can put this solution on YOUR website!
Use the Pythagorean Theorem:
a%5E2%2Bb%5E2=c%5E2
a%5E2%2B30%5E2=45%5E2
a%5E2%2B900=2025
Subtract 900 from both sides:
a%5E2=1125
Take the square root of both sides:
a=+sqrt%281125%29
This may need to be reduced with radicals or approximated to a decimal, whichever the problem requires.