SOLUTION: (fog)(x) for f(x)=2x-3 and g(x)=x^2 - 3x - 2 how do I work this out?

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: (fog)(x) for f(x)=2x-3 and g(x)=x^2 - 3x - 2 how do I work this out?      Log On


   

Question 748220: (fog)(x) for f(x)=2x-3 and g(x)=x^2 - 3x - 2 how do I work this out?
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
(fog)(x) =
f(g(x))=
2g(x)-3=
2(x^2 - 3x - 2)-3=
2x^2 - 6x - 7

:)