SOLUTION: If sin θ=square root of 3/2, which could not be the value of θ? 60 degrees 120 degrees 240 degrees 420 degrees

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Question 748174: If sin θ=square root of 3/2, which could not be the value of θ?
60 degrees
120 degrees
240 degrees
420 degrees
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The angle 240 degrees is in quadrant III where sine is negative. So sin(240) can't be sqrt(3)/2 since this is positive.

So the answer must be choice C