SOLUTION: (x^2-3)(x^2+3x-4)=0

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Question 74788This question is from textbook
: (x^2-3)(x^2+3x-4)=0 This question is from textbook

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%5E2-3%29%28x%5E2%2B3x-4%29=0
%28x%5E2-3%29=0Set each factor equal to zero
x=0%2B-sqrt%283%29There's one set of roots
%28x%5E2%2B3x-4%29=0
%28x%2B4%29%28x-1%29=0Factor the right side
x%2B4=0
x=-4
x-1=0
x=1
So the roots are
x=1, x=-4, x=sqrt%283%29 and x=-sqrt%283%29. Since this is a 4th degree polynomial, we have found all the roots and they are all real roots.