SOLUTION: Please help me solve this equation: {{{ 1/(m^2-m) + 1/(m) = 5/(m^2-m) }}}

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Question 747655: Please help me solve this equation: +1%2F%28m%5E2-m%29+%2B+1%2F%28m%29+=+5%2F%28m%5E2-m%29+

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1/(m^2-m) + 1/(m) = 5/(m^2-m)
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Multiply thru by m(m^2-m) to get:
m + m^2-m = 5m
m^2 - 5m = 0
m(m-5) = 0
m = 0 or m = 5
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"m" cannot be zero because it is one of the denominators.
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Solutiion: m = 5
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Cheers,
Stan H.