SOLUTION: How to solve this quadratic equation by completing the square x^2 + 6X - 7 = 0

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Question 7474: How to solve this quadratic equation by completing the square

x^2 + 6X - 7 = 0

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
ok, completing the square...

x%5E2%2B6x-7. First ignore the 7. Just think about the x%5E2%2B6x. What i want to do is think of the correct number (not the 7) that needs to be there so that I can factorise the quadratic as %28x%2Bk%29%5E2 where k is a "nice" number, usually an integer, sometimes a simple fraction, rarely a horrible number.

think about %28x%2Bk%29%5E2. This expands to be x%5E2+%2B+2kx+%2B+k%5E2, so we look at the coefficient before the x-term, our +6, and we note that this is like the "2k", so k must be 3. The number we therefore require %28k%5E2%29 is +9, so what we need is:

x%5E2%2B6x%2B9.

That is it done, really. All we have to do now is get this to look like the original, x%5E2%2B6x-7, as follows:

x%5E2%2B6x%2B9-9-7...note the +9-9 cancel each other out, leaving the -7
x%5E2%2B6x%2B9+-+16
%28x%2B3%29%5E2+-+16

Hope this is clear?

And now to answer the question... %28x%2B3%29%5E2+-+16+=+0

%28x%2B3%29%5E2+=+16
%28x%2B3%29+=+sqrt%2816%29 or %28x%2B3%29+=+-+sqrt%2816%29

so x+3 = 4 OR x+3 = -4
so x=1 OR x=-7

jon.