SOLUTION: Knowing that x = 2 and log(base a)y = 3 calculate the numerical value of the following a) log(base a)x^3y^2 b) log(base a) (a^3x^2/y^2) Can you please help me out? Thanks so

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Knowing that x = 2 and log(base a)y = 3 calculate the numerical value of the following a) log(base a)x^3y^2 b) log(base a) (a^3x^2/y^2) Can you please help me out? Thanks so       Log On


   

Question 747371: Knowing that x = 2 and log(base a)y = 3 calculate the numerical value of the following
a) log(base a)x^3y^2
b) log(base a) (a^3x^2/y^2)
Can you please help me out? Thanks so much in advance
Can you also show me the steps it would really help me understand:)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Knowing that x = 2 and log(base a)y = 3 calculate the numerical value of the following
a) log(base a)x^3y^2
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= loga(x^3)+loga(y^2)
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= 3loga(x) + 2loga(y)
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= 3loga(2) + 2loga(3)
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= loga(8) + loga(9)
---
= loga(72)
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b) log(base a) (a^3x^2/y^2)
----
= loga(a^3) + loga(x^2) - loga(y^2)
----
= 3 + 2loga(2) -2loga(3)
----
= 3 + loga(4) - loga(9)
---
= 3 + loga[4/9]
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Cheers,
Stan H.
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