SOLUTION: A father is 2 years younger than 3 times the age of his son. In 12 years, he will be 12 years younger than twice the age of his son will be. Find their present ages.
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Question 747065: A father is 2 years younger than 3 times the age of his son. In 12 years, he will be 12 years younger than twice the age of his son will be. Find their present ages. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A father is 2 years younger than 3 times the age of his son. In 12 years, he will be 12 years younger than twice the age of his son will be. Find their present ages.
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Equations:
f = 3s-2
f+12 = 2(s+12)-12
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Substitute for "f" and solve for "s":
3s-2+12 = 2s+24-12
s+10 = 12
s = 2 yrs old (son's age now)
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f = 3s-2 = 3*2-2 = 4 yrs old (father's age now)
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Note: That doesn't make much sense.
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Cheers,
Stan H.
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