SOLUTION: Four men and three women are seated in a seven-chair row. Find the probability of:
a) the women side by side
b) men and women alternate
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a) the women side by side
b) men and women alternate
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Question 746976: Four men and three women are seated in a seven-chair row. Find the probability of:
a) the women side by side
b) men and women alternate Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Four men and three women are seated in a seven-chair row. Find the probability of:
a) the women side by side
# of ways to succeed wwmmmm: mwwmmm: mmwwmm: mmmwwm: mmmmww-----5 ways
# of random arrangements 7!/(2!*3!) = 420
P(women side by side+ 5/420
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b) men and women alternate
# of ways to succeed: mwmwmwm----1 way
# of random arrangements: 420
P(altenage) = 1/420
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Cheers,
Stan H.
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