Question 746890: A(1,2), B(-1,1), C(1,0), D(-1,0) and P is (t,0). (cordinates of p are located between 0 and 1 on axis X), we are to find the point P at which angle APB is maximized
tan(APC) is = 2/1-t, tan(BPD) = 1/1+t and hence tan(APC) = t+x/t^2+y
therefore, the cordinates of point P are (t,0)
Answer by solver91311(24713) (Show Source):
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