SOLUTION: a circle of radius 5 with center at (2,7) has equation (x-2)squared+(y-7)squared=25. at which points does the line y=3 intersect with the circle

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: a circle of radius 5 with center at (2,7) has equation (x-2)squared+(y-7)squared=25. at which points does the line y=3 intersect with the circle       Log On


   

Question 746874: a circle of radius 5 with center at (2,7) has equation (x-2)squared+(y-7)squared=25. at which points does the line y=3 intersect with the circle
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
a circle of radius 5 with center at (2,7) has equation (x-2)squared+(y-7)squared=25. at which points does the line y=3 intersect with the circle
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%28x-2%29%5E2+%2B+%28y-7%29%5E2+=+25
Sub 3 for y
%28x-2%29%5E2+%2B+%283-7%29%5E2+=+25
%28x-2%29%5E2+%2B+16+=+25
%28x-2%29%5E2+=+9
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x - 2 = 3
x = 5 --> (5,3)
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x - 2 = -3
x = -1 --> (-1,3)