SOLUTION: In Triangle ABC, Angle B = 15 degrees less than twice angle A and Angle C is more than angle A. Find angle C.

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Question 746756: In Triangle ABC, Angle B = 15 degrees less than twice angle A and Angle C is more than angle A. Find angle C.
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
B=2A-15
C>A
and A+B+C=180
which becomes...
A+(2A-15)+C=180
C=180+15-3A
C=165-3A

so
0%3CA%3C55
Which sets our boundary to test for valid triangles. After trial and error (there's probably a better way) we can deduce the following.
The least value for C under these conditions is C=42 and the greatest is a little more than 142
so...these are pretty good approximations
8%3CA%3C41
42%3CC%3C142