SOLUTION: An object is propelled upward from the ground. The height of the object t seconds later is given by the equation h = -16tē + 32t , where h is measured in feet. After how many secon
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Question 746666: An object is propelled upward from the ground. The height of the object t seconds later is given by the equation h = -16tē + 32t , where h is measured in feet. After how many seconds does the object hit the ground? Answer by FrankM(1040) (Show Source):
You can put this solution on YOUR website! h = -16t^2 +32t
h= -16t (t-2) (factored out -16t from both terms_
for-16t to equal 0, t = 0, i.e. object starts at ground
t-2 = 0 at t = 2, so object isback down at 2 seconds.
