SOLUTION: Find the solution of the equation in the interval [0,2pi) algebraically.
sin^2x+cosx+1=0
Some quick help would be greatly appreciated.
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-> SOLUTION: Find the solution of the equation in the interval [0,2pi) algebraically.
sin^2x+cosx+1=0
Some quick help would be greatly appreciated.
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Question 746610: Find the solution of the equation in the interval [0,2pi) algebraically.
sin^2x+cosx+1=0
Some quick help would be greatly appreciated. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Find the solution of the equation in the interval [0,2pi) algebraically.
sin^2x+cosx+1=0
1-cos^2x+cosx+1=0
cos^2x-cosx-2=0
(cosx-2)(cosx+1)=0
cosx=2 (reject,(-1 ≤ cosx ≤ 1))
or
cosx=-1
x=π
(