SOLUTION: log10(3m-5) +log10m=log10 2
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Question 746511
:
log10(3m-5) +log10m=log10 2
Answer by
lwsshak3(11628)
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log10(3m-5) +log10m=log10 2
log(3m-5)m=log(2)
3m^2-5m=2
3m^2-5m-2=0
(3m+1)(m-2)=0
m=-1/3(reject, m>0
or
m=2