SOLUTION: Five balls are selected at random without replacement from an urn containing four white balls and five blue balls. Find the probability that two or three of the balls are white.
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Question 746427: Five balls are selected at random without replacement from an urn containing four white balls and five blue balls. Find the probability that two or three of the balls are white. Please show me how to work this Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Five balls are selected at random without replacement from an urn containing four white balls and five blue balls.
Find the probability that two or three of the balls are white. Please show me how to work this.
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P(2 white) = 4C2/9C2
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P(3 white) = 4C3/9C3
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P(2 white OR 3 white) = 6/36 + 4/84 = (1/6)+(1/26)= (32)/[6*26] = 8/39
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Cheers,
Stan H.
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