Question 746193: Please help me solve this equation. I am having trouble finding all the steps.
log(16+2x)=log(x^2-4x) Found 2 solutions by josgarithmetic, savvyhush23:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! You read that as, in a more general way, the logarithm of this expression equals the logarithm of that expression. So we must expect that "this" expression is equal to "that" expression. There is a way to make this much more formal, but doing so should be unnecessary.
No steps to get confused, unless you are unfamiliar with quadratic equations.
You can put this solution on YOUR website! Please help me solve this equation. I am having trouble finding all the steps.
log(16+2x)=log(x^2-4x)
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Is it finding x value in order for the function to be equal?
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If that so, since both side is in logarithm, you can eliminate log leaving: move 16 + 2x to the right, the function is a quadratic equation, therefore to find x, use quadratic formula:
a = 1, b = -6 and c = -16
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Therefore the answer are 8 and -2
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