SOLUTION: Jonathan leaves home at 07:45 and arrives at the office at 09:30. The journey is 42 miles
(b)What is his average speed for the journey?(in miles per hour)
i have tried doing di
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-> SOLUTION: Jonathan leaves home at 07:45 and arrives at the office at 09:30. The journey is 42 miles
(b)What is his average speed for the journey?(in miles per hour)
i have tried doing di
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Question 745874: Jonathan leaves home at 07:45 and arrives at the office at 09:30. The journey is 42 miles
(b)What is his average speed for the journey?(in miles per hour)
i have tried doing distance divided by time but it doesnt work out
42miles divided by 1 and 45/60 = 24 m/per hour im very confused :( Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Jonathan leaves home at 07:45 and arrives at the office at 09:30.
The journey is 42 miles.
:
I think you are on the right track, maybe if I just run thru it,
it will clarify things in your mind
:
Find his travel time: 09:30 - 07:45 = 1 hr 45 min
change 1 hr 45 to hrs: 1 + 45/60 = 1.75 hrs (decimals will work here)
:
Speed = dist/time
S =
S = 24 mph is the av speed
:
:
We can check that by finding the distance using a time of 1.75 hrs and 24 mph
1.75 * 24 = 42 mi
