SOLUTION: I need to find the real solutions of this: x^3-5x^2+8x-4

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Question 74574: I need to find the real solutions of this:
x^3-5x^2+8x-4

Answer by galactus(183) About Me  (Show Source):
You can put this solution on YOUR website!
Start by finding the factors of the constant 4. They are +/-[1,2,4]
So, divide the cubic by (x-1),(x+1),(x-2),(x+2),(x-4),(x+4). Upon division, does any of these cause the cubic to reduce to a quadratic?.
Yes, (x-2) and (x-1).
%28x%5E3-5x%5E2%2B8x-4%29%2F%28x-2%29=x%5E2-3x%2B2
So, x-2 is a factor.
Next, factor the resulting quadratic. That's easy.
x%5E2-3x%2B2=%28x-2%29%28x-1%29
So, the factored form of the cubic is %28x-2%29%5E2%28x-1%29