SOLUTION: I don't know if this is in the correct area but, I will try anyways. I don't understand how to get Rational Zeros from this equation at all. The equation is 2x^3+4x^2-22x-24.

Algebra ->  Rational-functions -> SOLUTION: I don't know if this is in the correct area but, I will try anyways. I don't understand how to get Rational Zeros from this equation at all. The equation is 2x^3+4x^2-22x-24.       Log On


   

Question 74573: I don't know if this is in the correct area but, I will try anyways.
I don't understand how to get Rational Zeros from this equation at all.
The equation is 2x^3+4x^2-22x-24.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
2x^3+4x^2-22x-24=0
x^3+2x^2-11x-12 = 0
Notice that f(-1)=0 so x=-1 is a zero.
Use synthetic division to find the quotient after dividing by (x+1):
-1....1....2....-11....-12
.......1....1.....-12..|..0
So, x^2+x-12 is the other factor after dividing:
It factors into (x+4)(x-3)
Therefore x=-4, and x=3 are also zeroes.
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Cheers,
Stan H.