Question 745468: The ordinate of a point which is √29 units from (5,1) is twice its abscissa. Find the point.
Answer by sachi(548)   (Show Source):
You can put this solution on YOUR website! as per question the point is (x,2x)
so the distance from (5,1)
is √[(x-5)^2+(2x-1)^2]=√29
or (x-5)^2+(2x-1)^=29
or x^2-10x+25+4x^2-4x+1=29
or 5x^2-15x-3=0
or 5x^2-15x-x-3=0
or (x-3)(5x+1)=0
or x=3 or -1/5
so y=6 or -2/5
so the points are (3,6) or (-1/5,-2/5)
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