SOLUTION: A chemist has 20% and 60% solution of acid available. How many liters of each solution should be mixed to obtain 10 liters of a 30% acid solution?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A chemist has 20% and 60% solution of acid available. How many liters of each solution should be mixed to obtain 10 liters of a 30% acid solution?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 745229: A chemist has 20% and 60% solution of acid available. How many liters of each solution should be mixed to obtain 10 liters of a 30% acid solution?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A chemist has 20% and 60% solution of acid available. How many liters of each solution should be mixed to obtain 10 liters of a 30% acid solution?
----
Equation:
0.20x + 0.60(10-x) = 0.30*10
--------
20x + 60*10 - 60x = 30*10
-40x = -30*10
x = (3/4)10
x = 7.5 liters (amt. of 20% solution needed)
10-x = 2.5 liters (amt. of 60% solution needed)
================================================
Cheers,
Stan H.
===================