SOLUTION: a bag contains 2 red, 4 yellow, and 6 blue marbles. two marbles are drawn without replacement. find the probability that neither is red and neither is blue.
Please help me to solv
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Please help me to solv
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Question 745190: a bag contains 2 red, 4 yellow, and 6 blue marbles. two marbles are drawn without replacement. find the probability that neither is red and neither is blue.
Please help me to solve this problem. Thank you so much. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a bag contains 2 red, 4 yellow, and 6 blue marbles. two marbles are drawn without replacement. find the probability that neither is red and neither is blue.
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They must both be yellow:
# of ways to succeed: 4C2 = (4*3)/(1*2) = 6
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# of possible outcomes: 12C2 = (12*11)/(1*2) = 66
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P(2 yellow) = 6/66 = 1/11
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Cheers,
Stan H.
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