SOLUTION: A club has 20 males and 11 females. if 4 kids are chosen, what is the probability 2 will be male and 2 will be female?
Algebra ->
Probability-and-statistics
-> SOLUTION: A club has 20 males and 11 females. if 4 kids are chosen, what is the probability 2 will be male and 2 will be female?
Log On
Question 745082: A club has 20 males and 11 females. if 4 kids are chosen, what is the probability 2 will be male and 2 will be female? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A club has 20 males and 11 females. if 4 kids are chosen, what is the probability 2 will be male and 2 will be female?
-------
# of ways to succeed: 20C2*11C2 = 190*55 = 10450
---
# of possible groups of 4: 31C4 = (31*30*29*28)/(1*2*3*4) = 31465
-----------
p(2MALE and 2FEMALE) = 10450/31465 = 0.332
===============
Cheers,
Stan H.
===============