SOLUTION: 1) At 6 a.m., a passenger train and a freight train leave stations that
are 360 miles apart and travel toward each other. The passenger train averages twice the speed of the frei
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: 1) At 6 a.m., a passenger train and a freight train leave stations that
are 360 miles apart and travel toward each other. The passenger train averages twice the speed of the frei
Log On
Question 744989: 1) At 6 a.m., a passenger train and a freight train leave stations that
are 360 miles apart and travel toward each other. The passenger train averages twice the speed of the freight train. At 10 a.m., the trains pass each other.
Write and solve an equation to find the average speed of each train Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Think of one train as standing still and the
other approaching at the sum of their speeds
( it doesn't matter which train is moving )
--------------------------------------
Let = the speed of the slower train = the speed of the faster train
The time the moving train is traveling is
10 AM minus 6 AM = hrs
----------------------------
The average speed of the freight train is 30 mi/hr
The average speed of the passenger train is 60 mi/hr
---------------
check:
freight train:
---------------
passenger train:
-------------- mi
OK
