SOLUTION: what is the diagonal, in feet, of a square with each side measuring 6 radical 2 feet

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Question 744983: what is the diagonal, in feet, of a square with each side measuring 6 radical 2 feet
Found 2 solutions by algebrahouse.com, Alan3354:
Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
A right triangle is formed with two legs of 6√2 ft and the diagonal as the hypotenuse.

a² + b² = c² {the Pythagorean Theorem}
(6√2)² + (6√2)² = c² {substituted 6√2 in for the legs, a and b}
36(2) + 36(2) = c² {evaluated the exponents}
72 + 72 = c² {multiplied}
144 = c² {added}
c = 12 {took the square root of each side}

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Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
what is the diagonal, in feet, of a square with each side measuring 6 radical 2 feet
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It's not "6 radical 2", it's 6* square root of 2.
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d%5E2+=+%286sqrt%282%29%29%5E2+%2B+%286sqrt%282%29%29%5E2+=+36%2A2+%2B+36%2A2+=+144
d = 12 feet