SOLUTION: Four years ago, Adrian was a quarter of his brother's age. In two years time, if Adrian's age is doubled it will match his brother's age. How old is Adrian now?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Four years ago, Adrian was a quarter of his brother's age. In two years time, if Adrian's age is doubled it will match his brother's age. How old is Adrian now?      Log On


   

Question 744790: Four years ago, Adrian was a quarter of his brother's age. In two years time, if Adrian's age is doubled it will match his brother's age. How old is Adrian now?
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
A-Adrian's age
B-Brother's age
A-4=%281%2F4%29B <---1
2%28A%2B2%29=B <---2

simplifying...
1--->4A-16=B
2--->2A%2B4=B
Since both equations are in terms of B we set them equal then solve for A


4A-16=2A%2B4
4A-2A=4%2B16
2A=20
A=10
Adrian is 10 years old