SOLUTION: I have a question- what equation do I use to work out the angles in a right angled triangle if there is a 5.6m line extending up the y axis and a 3.6m line extending along the x

Algebra ->  Trigonometry-basics -> SOLUTION: I have a question- what equation do I use to work out the angles in a right angled triangle if there is a 5.6m line extending up the y axis and a 3.6m line extending along the x      Log On


   

Question 74475: I have a question-
what equation do I use to work out the angles in a right angled triangle if there is a 5.6m line extending up the y axis and a 3.6m line extending along the x axis - both at a right angle to each other. There is an angled line from the top of the 5.6m line to the end of the 3.6m line. The angle i'm after is between the top of the 5.6m line to the line extended to the end of the 3.6m line.??? If you could help me out it would be great!!!
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
Do they still teach SOHCAHTOA in school?

It is an acronym for remembering the trigonometric relationships in a right triangle.

sine=opposite%2Fhypotenuse

cosine=adjacent%2Fhypotenuse

tangent=opposite%2Fadjacent

In your problem, you know the length of the side opposite the angle (3.6m); and the length of the side adjacent to the angle (5.6m).

Using the tangent function: tan%28x%29=3.6%2F5.6 or tan%28x%29=9%2F14

To find the angle; you use the inverse or arctangent function, sometimes written as tan with a (-1) exponent

arctan%289%2F14%29=32.74 or 32.74 degrees