SOLUTION: the present age of a father is equal to the sum of ages of his 5 children. 12 years hence the sum of ages of his children will be twice the age of their father. find the present ag
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Question 744574: the present age of a father is equal to the sum of ages of his 5 children. 12 years hence the sum of ages of his children will be twice the age of their father. find the present age of the father. Found 4 solutions by lynnlo, ankor@dixie-net.com, ikleyn, josgarithmetic:Answer by lynnlo(4176) (Show Source):
You can put this solution on YOUR website! the present age of a father is equal to the sum of ages of his 5 children.
f = a+b+c+d+e
:
12 years hence the sum of ages of his children will be twice the age of their father.
a+12 + b+12 + c+12 + d+12 + e+12 = 2(f+12)
a+b+c+d+e + 60 = 2f + 24
Replace a+b+c+d+e with f
f + 60 = 2f + 24
60 - 24 = 2f - f
36 = f
:
find the present age of the father. He's 36 yrs old
You can put this solution on YOUR website! .
the present age of a father is equal to the sum of ages of his 5 children.
12 years hence the sum of ages of his children will be twice the age of their father.
find the present age of the father.
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Let x be the present age of the father.
According to the problem, x is equal to the sum of the 5 his children, at the same time.
12 years later, the sum of ages of 5 children will be x+5*12 = x+60 years.
At that time the age of the father will be x+12 years.
The problem says that
2(x+12) = x + 5*12.
To find x, simplify this equation step by step
2x + 24 = x + 60
2x - x = 60 - 24
x = 36.
ANSWER. The father is 36 years old now.
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