SOLUTION: Two numbers differ by 5, and one-half of the larger exceeds one-sixth of the smaller by 8. Find the two numbers.
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Question 744531: Two numbers differ by 5, and one-half of the larger exceeds one-sixth of the smaller by 8. Find the two numbers. Answer by sachi(548) (Show Source):
You can put this solution on YOUR website! Two numbers differ by 5,
so if one no is x the other is x-5
one-half of the larger exceeds one-sixth of the smaller by 8
so x/4=(x-5)/6+8
or 3x=2(x-5)+96 multiplying 12 throughout
or 3x=2x-10+96=2x+86
or 3x-2x=86
or x=86
the smaller no=86-5=81
